CuOs - H2g - Cus - H2Ol In this reaction- is reduced-

The correct option is A copper oxide CuO(s) + H_2(g) → Cu(s) + H_2O(l) In this reaction hydrogen gains oxygen and forms water, hence it is oxidised. On the ...

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Byju's Answer

Standard X

Chemistry

Double Displacement Reaction

CuOs + H2g → ...

Question

$C u O (s) + H_{2} (g) \to C u (s) + H_{2} O (l)$
In this reaction, _______ is reduced.

copper oxide

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copper

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hydrogen

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water

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Solution

The correct option is A copper oxide
$C u O (s) + H_{2} (g) \to C u (s) + H_{2} O (l)$
In this reaction hydrogen gains oxygen and forms water, hence it is oxidised. On the other hand copper oxide loses oxygen and hence reduced.

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Similar questions

Identify the substances that are oxidised and the substances that are reduced in the following reactions.

(i)

(ii)

Q. Justify that the following reactions are redox reactions:

C u O (s) + H_{2} (g) \to C u (s) + H_{2} O (g)

Q. What are redox reactions? Identify the substances that are oxidised and the substances that are reduced in the following reactions?
A.

2 H_{2} S_{(g)} + S O_{2 (g)} \to 3 S_{(s)} + 2 H_{2} O_{(1)}

C u O_{(s)} + H_{2 (g)} \to C u_{(s)} + H_{2} O

Q. For the reaction

C u O (s) + H_{2} (g) \to C u (s) + H_{2} O (l)

Which of the following statement is correct?

Q. Recorded data:
Before

:

C u O +

porcelain boat

= 62.869 g

C a C l_{2} +

U-tube

= 80.483 g

After:Porcelain boat

+

contents

= 54.869 g

C a C l_{2} + U

-tube

= 89.483 g

Reactions:

Z n (s) + 2 H C l (a q) \to Z n C l_{2} (a q) + H_{2} (g)

then

H_{2} (g) + C u O (s) \to H_{2} O (g) + C u (s)

What conclusion can you draw after the completion of this experiment?

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CuO(s)+H2(g)→Cu(s)+H2O(l) In this reaction, _______ is reduced.

The correct option is A copper oxideCuO(s)+H2(g)→Cu(s)+H2O(l)In this reaction hydrogen gains oxygen and forms water, hence it is oxidised. On the other hand copper oxide loses oxygen and hence reduced.

$C u O (s) + H_{2} (g) \to C u (s) + H_{2} O (l)$
In this reaction, _______ is reduced.

The correct option is A copper oxide
$C u O (s) + H_{2} (g) \to C u (s) + H_{2} O (l)$
In this reaction hydrogen gains oxygen and forms water, hence it is oxidised. On the other hand copper oxide loses oxygen and hence reduced.