D, E, F are the midpoints of the sides BC, CA and AB respectively of △ ABC. Then △ DEF is congruent to triangle –
AEF
BFD, CDE
AFE, BFD, CDE
It is easy to verify that △ DEF is congruent to each one of the triangles △ AEF, △ BFD & △ CDE.
Consider ΔAFE∠AFE=∠Band∠AEF=∠C
Since FE is parallel to BC.
Similarly in ΔBFD∠BFD=∠Aand∠BDF=∠C and
ΔDEC∠DEC=∠Aand∠EDC=∠B
We know ∠A+∠B+∠C=180∘
Now, consider ΔDEF∠FED=180∘−∠DBF−∠EDC=180−∠C−∠B=∠A
Similarly, ∠DFE=∠C and ∠FED=∠B.
By AA similarity
So, ΔDEF~ΔAFE~ΔBFD~ΔCDE