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Question

D, E, F are the midpoints of the sides BC, CA and AB respectively of ABC. Then DEF is congruent to triangle –


A

ABC

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B

AEF

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C

BFD, CDE

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D

AFE, BFD, CDE

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Solution

The correct options are
B

AEF


C

BFD, CDE


D

AFE, BFD, CDE


It is easy to verify that DEF is congruent to each one of the triangles AEF, BFD & CDE.

Consider ΔAFEAFE=BandAEF=C

Since FE is parallel to BC.

Similarly in ΔBFDBFD=AandBDF=C and

ΔDECDEC=AandEDC=B

We know A+B+C=180

Now, consider ΔDEFFED=180DBFEDC=180CB=A
Similarly, DFE=C and FED=B.
By AA similarity
So, ΔDEF~ΔAFE~ΔBFD~ΔCDE


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