Question 58 (d)
Subtract:
x4+3x3y3+5y4 from 2x4−x3y3+7y4.
We have, 2x4−x3y3+7y4−(x4+3x3y3+5y4) = 2x4−x3y3+7y4−x4−3x3y3−5y4 On combining the like terms, = 2x4−x4−x3y3−3x3y3+7y4−5y4=x4−4x3y3+2y4