Question

$d_{x^2-y^2}$ orbital is not involved in which of the following hybridization?

• A. $s{p}^{3}d(sq.pyramidal)$
• B. $ds{p}^2$
• C. $s{p}^3{d}^2$
• D. None of these

Answer 1

The correct option is D

None of these

$s{p}^{3}d\Rightarrow s{p}_x{p}_y{p}_z{d}_{x^2-y^2}ds{p}^3\Rightarrow d_{x^2-y^2}s{p}_x{p}_y{p}_{z}s{p}^3{d}^2\Rightarrow s{p}_x{p}_y{p}_z{d}_{x^2-y^2}{d}_{z^2}s{p}^3{d}^3\Rightarrow s{p}_x{p}_y{p}_z{d}_{x^2-y^2}{d}_{z^2}{d}_{xy}$