Daniel cell can be represented in which of the following way?
A
Zn(s)|Zn2+(aq)||Cu(s)|Cu2+(aq)
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B
Zn(s)|Zn2+(aq)||Cu2+(aq)|Cu(s)
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C
Cu(s)|Cu2+(aq)||Zn2+(aq)|Zn(s)
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D
Zn2+(aq)|Zn(s)||Cu2+(aq)|Cu(s)
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Solution
The correct option is BZn(s)|Zn2+(aq)||Cu2+(aq)|Cu(s) In daniel cell, zinc gets oxidized (as anode) and Cu gets reduced(cathode). ∴ Correct cell representation: Zn(s)|Zn2+(aq)||Cu2+(aq)|Cu(s).