Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint $100m^2$of area is painted. How many cans of paint will she need to paint the room?

Answer 1

Here, Length of wall l = 15 m, Breadth of wall b= 10 m
And Height of wall h= 7 m
Total Surface area of classroom to be painted = lb+2(bh+hl)
$=15\times 10+2(10\times 7+7\times 15)$
$=150+2(70+105)$
$=150+350$
$=500m^2$
$\text{Now Required number of cans}=\frac{Areaofhall}{Areaofonecan}=\frac{500}{100}=5cans$
Hence, 5 cans are required to paint the room.