Question

de-Broglie relation can be equivalent to Bohrs quantum theory if one considers

• A. 2$\pi r=n\lambda$
• B. $r=n\lambda$
• C. $\lambda =\frac{h}{mv}$
• D. none of these

Answer 1

The correct option is A 2$\pi r=n\lambda$

The circumference of the orbit has to be an integral multiple of debroglie wavelength
for constructive interference and stability
$n\lambda =2\pi r$
De broglie wavelength
$\lambda =\frac{h}{mv}$
$mvr=\frac{nh}{2\pi }$