De-Broglie wavelength of an electron travelling with speed equal to 1% of the speed of light is?
A
400pm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
120pm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
242pm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
375pm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C242pm According to De-Broglie relation: λ=hmv---(i) Mass of electron = 9.1×10−31 kg Velocity is 1% the speed of light i.e v=c×1100=3×108×0.01=3×106m/s Putting all the values in (i) gives, λ=6.6×10−349.1×10−31×3×106 =0.242m or ⇒λ=242pm.