Decreasing order of stability of O 2- O 2- O 2-and O 22- is -A- O 2- O 2- O 22- O 2-B- O 2- O 22- O 2- O 2C- O 2- O 2- O 2- O 22-D- O 22- O 2- O 2- O 2-

The correct option is C O_2^+ gt;O_2 gt;O_2^ gt;O_2^2 Given species : O_2, O_2^ ,O_2^+,O_2^2 Total number of electrons in each species: O_2→ 16e^ O_2^ ...

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Byju's Answer

Standard XII

Chemistry

Molecular Orbitals of Oxygen

Decreasing or...

Question

Decreasing order of stability of $O_{2}, O_{2}^{-}, O_{2}^{+}$ and $O_{2}^{2 -}$ is :-

O_{2} > O_{2}^{+} > O_{2}^{2 -} > O_{2}^{-}

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O_{2}^{-} > O_{2}^{2 -} > O_{2}^{+} > O_{2}

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O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}

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O_{2}^{2 -} > O_{2}^{-} > O_{2} > O_{2}^{+}

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Solution

The correct option is C $O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}$
Given species : $O_{2}, O_{2}^{-}, O_{2}^{+}, O_{2}^{2 -}$
As the bond order decreases, the stability decreases.
Total number of electrons in each species:
$O_{2} \to 16 e^{-}$
$O_{2}^{-} \to 17 e^{-}$
$O_{2}^{+} \to 15 e^{-}$
$O_{2}^{2 -} \to 18 e^{-}$
$B o n d o r d e r o f O_{2}^{+}$ = 2.5 , $O_{2} = 2, O_{2}^{2 -} = 1, O^{2 -} = 1.5$
Stability $\propto$ B.O
$∴$ Stability order $[O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{2 -}]$

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Similar questions

Q. What is the stability order of the following species?

O_{2}^{2 +}

O_{2}^{+}

O_{2}

O_{2}^{-}

O_{2}^{2 -}

Q. Which of the following orders is correct for the bond dissociation energy of

O_{2}^{+}, O_{2}, O_{2}^{-}

and

O_{2}^{2 -}

Q. Decreasing order of stability of

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and

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is:

Q. Decreasing order of stability of

O_{2}

O_{2}^{-}

O_{2}^{+}

, and

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and

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Decreasing order of stability of O2,O−2,O+2 and O2−2 is :-

Decreasing order of stability of $O_{2}, O_{2}^{-}, O_{2}^{+}$ and $O_{2}^{2 -}$ is :-