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Byju's Answer
Standard XII
Chemistry
Bond Order and Enthalpy
Which of the ...
Question
Which of the following orders is correct for the bond dissociation energy of
O
+
2
,
O
2
,
O
−
2
and
O
2
−
2
?
A
O
+
2
>
O
2
>
O
−
2
>
O
2
−
2
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B
O
+
2
>
O
2
<
O
2
<
O
2
−
2
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C
O
+
2
<
O
2
<
O
2
<
O
2
−
2
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D
O
+
2
>
O
2
>
O
2
−
2
>
O
−
2
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Solution
The correct option is
A
O
+
2
>
O
2
>
O
−
2
>
O
2
−
2
Bond Order
=
Bonding electrons
−
Antibonding electrons
2
O
2
−
2
→
Total electron = 16 + 2 = 18
Configuration:
σ
(
1
s
)
2
σ
∗
(
1
s
)
2
σ
(
2
s
)
2
σ
∗
(
2
s
)
2
σ
(
2
p
z
)
2
π
(
2
p
x
)
2
π
(
2
p
y
)
2
π
∗
(
2
p
x
)
2
π
∗
(
2
p
y
)
2
Bond Order
=
10
−
8
2
=
1
O
−
2
→
Total electron = 16 +1 = 17
Configuration:
σ
(
1
s
)
2
σ
∗
(
1
s
)
2
σ
(
2
s
)
2
σ
∗
(
2
s
)
2
σ
(
2
p
z
)
2
π
(
2
p
x
)
2
π
(
2
p
y
)
2
π
∗
(
2
p
x
)
2
π
∗
(
2
p
y
)
1
Bond Order
=
10
−
7
2
=
1.5
O
2
→
Total electron = 8 + 8 = 16
Configuration:
σ
(
1
s
)
2
σ
∗
(
1
s
)
2
σ
(
2
s
)
2
σ
∗
(
2
s
)
2
σ
(
2
p
z
)
2
π
(
2
p
x
)
2
π
(
2
p
y
)
2
π
∗
(
2
p
x
)
1
π
∗
(
2
p
y
)
1
Bond Order
=
10
−
6
2
=
2
O
+
2
→
Total electron = 16 -1 = 15
Configuration:
σ
(
1
s
)
2
σ
∗
(
1
s
)
2
σ
(
2
s
)
2
σ
∗
(
2
s
)
2
σ
(
2
p
z
)
2
π
(
2
p
x
)
2
π
(
2
p
y
)
2
π
∗
(
2
p
x
)
1
Bond Order
=
10
−
5
2
=
2.5
Hence, the correct bond order in the following species is:
O
+
2
>
O
2
>
O
−
2
>
O
2
−
2
Bond order
∝
Bond dissociation enthalpy
Order:
O
+
2
>
O
2
>
O
−
2
>
O
2
−
2
Suggest Corrections
3
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,
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Q.
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Standard XII Chemistry
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