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Question

Define least count of a vernier callipers. How do you determine it ?

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Solution

The least count of vernier callipers is equal to the difference between the values of one main scale division and one vernier scale division.
Let n divisions on vernier callipers be of length equal to that of (n – 1) divisions on the main scale and the value of 1 main scale division be x. Then,
Value of n divisions on vernier = (n – 1) x
a l t e r n a t i v e l y comma v a l u e space o f space 1 space d i v i s i o n space 1 space v e r n i e r equals fraction numerator open parentheses n minus 1 close parentheses x over denominator n end fraction h e n c e l e a s t space c o u n t equals x minus fraction numerator open parentheses n minus 1 close parentheses x over denominator n end fraction equals x over n L. C equals fraction numerator v a l u e space o f space 1 space m a i n space s c a l e space d i v i s i o n over denominator t o t e l space n o space o f space d i v i s i o n space o n space v e r n i e r space c a l i p e r s end fraction v a l u e space o f space 1 space m a i n space s c a l e space d i v i s i o n equals 1 m m t o t e l space n o space o f space d i v i s i o n s space o n space v e r n i e r equals 10 t h e r f o r e comma L. C equals fraction numerator 1 m m over denominator 10 end fraction equals 0.1 m m equals 0.01 c m


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