Question

Define normality $6.3gms$ of oxalic acid is present in $500ml$ of solution its normality is:

Answer 1

Normality is defined as the number of mole equivalents per litre of solution.

Oxalic acid $C_2{H}_2{O}_4.2H_{2}O$

Molecular mass $=126g$

Equivalent weight $=\frac{126}{2}=63g/equiv$

Normality $=\frac{\text{weight}}{\text{Eq. wt.}\times 1000}=\frac{6.3}{63\times \frac{500}{1000}}=0.1\times 2=0.2N$