Question

Degree of dissociation of $0.1N$ ${CH}_{3}COOH$ is: $(K_a=1.0\times {10}^{-5}$)

• A. ${10}^{-5}$
• B. ${10}^{-4}$
• C. ${10}^{-3}$
• D. ${10}^{-2}$

Answer 1

The correct option is D ${10}^{-2}$

$\alpha =\sqrt{\frac{K_a}{C}}$

$\alpha =\sqrt{\frac{1\times {10}^{-5}}{0.1}}=\sqrt{\frac{1\times {10}^{-5}}{1\times {10}^{-1}}}=\sqrt{{10}^{-4}}={\left({10}^{-4}\right)}^{1/2}={10}^{-2}$