Question

$\Delta$ABC is the isosceles triangle where seg AB$\cong$ seg AC write two different congruent correspondences between the vertices, by which $\Delta$ABC is congruent to itself.

Answer 1

In $△ABC$ and $△ACB$
seg $AB\cong$ seg $AC$ (Given)
$\angle ABC=\angle ACB$ (Isosceles triangle property)
$\angle BAC=\angle CAB$ (Common angle)
Thus, $△ABC\cong △ACB$ (ASA postulate)
Also, Any triangle will be congruent to itself. hence, $△ABC\cong △ABC$