Question

$\Delta G^0$ for the reaction : $X+Y\rightleftharpoons C$ is -4.606 kcal at 1000K. The equilibrium constant for the reverse mode of the reaction is :

• A. 100
• B. 10
• C. 0.01
• D. 0.1

Answer 1

The correct option is D 0.1

$X+Y\rightleftharpoons C$ ${\Delta G}^0=-4.606$ Kcal at 1000K

Suppose K be equilibrium constant

${\Delta G}^0=-RTIn\left(K_{eq}\right)$

$+4.606\times {10}^3=12\times {10}^{3}In\left(K_{eq}\right)$

$2.303=In\left(K_{eq}\right)$

$K_{eq}=10$

So reverse reaction equilibrium constant equal to $1/K_{eq}$ $=0.1$