Question

$\Delta G^{\circ }$ for the reaction $x+y\rightleftharpoons z$ is $-4.606kcal$. The value of equilibrium constant of the reaction at ${227}^{\circ }C$ is

• A. 100
• B. 10
• C. 2
• D. 0.01

Answer 1

The correct option is A

100

$\Delta G^{\circ }=-2.303RTlog{k}_p$

$-4.606=-2.303\times 2\times {10}^{-3}\times 500$ by $K_f$

$log{k}_p=\frac{1000}{500}=2$

$k_p={10}^2=100$