- Gfo standard free energy of formation of ZnO and CO are -318-2 kJ mol -1 and -137-3 kJ mol -1 respectively- ZnO-C - Zn - CO The approximate value of - Gfo in kJmol -1 for the above reaction is kJ mol -1-Write your answer in form of inearest integer-

Zn #160; + #160; 12 O_2 → ZnO #160; , Δ G_f^o = 318.2 kJ/mol C +12 O_2 → CO , Δ G_f^o = #160; 137.3 kJ/mol ZnO+C ⟶ Zn + CO ...

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Standard XII

Chemistry

Second Law of Thermodynamics

Δ Gfo standar...

Question

$Δ G_{f}^{o}$ (standard free energy of formation) of $Z n O$ and $C O$ are -318.2 kJ mol $^{- 1}$ and -137.3 kJ mol $^{- 1}$ respectively.

$Z n O + C ⟶ Z n + C O$

The approximate value of $Δ G_{f}^{o}$ in kJmol $^{- 1}$ for the above reaction is _______kJ mol $^{- 1}$ .
[Write your answer in form of inearest integer]

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Solution

$Z n + \frac{1}{2} O_{2} \to Z n O$ , $Δ G_{f}^{o}$ = - 318.2 kJ/mol

$C + \frac{1}{2} O_{2} \to C O$ , $Δ G_{f}^{o}$ = -137.3 kJ/mol

$Z n O + C ⟶ Z n + C O$

$Δ G^{o} = Δ G_{f}^{o} (C O) - Δ G_{f}^{o} (Z n O)$

$= - 137.3 - (- 318.2)$

$= 180.9 \approx 181$ kJ mol $^{- 1}$

Positive value of $Δ G^{o}$ indictes that reaction is non-spontaneous.
(However, it is spontaneous above 1000 $^{o}$ C).

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ΔGof (standard free energy of formation) of ZnO and CO are -318.2 kJ mol−1 and -137.3 kJ mol−1 respectively. ZnO+C⟶Zn+CO The approximate value of ΔGof in kJmol−1 for the above reaction is _______kJ mol−1.[Write your answer in form of inearest integer]

Zn+12 O2→ZnO , ΔGof = - 318.2 kJ/molC+12O2→CO , ΔGof = -137.3 kJ/molZnO+C⟶Zn+COΔGo=ΔGof(CO)−ΔGof(ZnO)=−137.3−(−318.2)=180.9≈181 kJ mol−1Positive value of ΔGo indictes that reaction is non-spontaneous. (However, it is spontaneous above 1000oC).