Question

$\Delta PQR\sim \Delta LTR$. In $\Delta PQR$, PQ = 4.2 cm, QR = 5.4 cm, PR = 4.8 cm.
Construct $\Delta PQR$ and $\Delta LTR$, such that $\frac{RQ}{RT}=\frac{7}{5}$, then the measure of LT is equal to ____ cm.

• A. 5.2 cm
• B. 4.8 cm
• C. 3.6 cm
• D. 3 cm

Answer 1

The correct option is D 3 cm

Steps of construction :

1. Construct $\Delta PQR$.
2. Divide segment QR into 7 equal parts and mark the 5${}^{th}$ point as T.
3. Draw a line parallel to side PQ, through T. Name the point of intersection of the line and ray PR as L.

We get the required $\Delta PQR\sim \Delta LTR$.


Measure the value of LT, we get LT = 3cm.