Densities of two gases are in the ratio $1 : 2$ and their temperatures are in the ratio $2 : 1$ then the ratio of their respective pressures is:

1 : 1

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1 : 2

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2 : 1

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4 : 1

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Solution

The correct option is A $1 : 1$
As we know,
$P = \frac{d R T}{M}$
$P \propto d and T, \frac{P_{1}}{P_{2}} = \frac{d_{1} T_{1}}{d_{2} T_{2}} = \frac{1}{2} \times \frac{2}{1} \Rightarrow P_{1} : P_{2} = 1 : 1$

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