The ratio of the pressure of two gases at the same temperature if their densities are in the ratio 2:1 and their molecular mass ratio is 1:2 is :

1:2

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4:1

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1:4

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2:1

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Solution

The correct option is B 4:1
According to ideal gas equation:
$P V = \frac{w}{M} R T$

$P M = d R T$

Given,
$\frac{d_{1}}{d_{2}} = \frac{2}{1}$

$\frac{M_{1}}{M_{2}} = \frac{1}{2}$
$\frac{P_{1} M_{1}}{P_{2} M_{2}} = \frac{d_{1}}{d_{2}}$
$\frac{P_{1}}{P_{2}} = \frac{2}{1} \times \frac{2}{1} = 4 : 1$

Hence, option B is correct.

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Densities of two gases are in the ratio 1 : 2 and their temperatures are in the ratio 2 : 1, then the ratio of their respective pressures is

1 : \frac{1}{\sqrt{2}} : \frac{1}{\sqrt{3}}

A, B

C

1 : \frac{1}{\sqrt{2}} : \frac{1}{\sqrt{3}}

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