Question

# Density of ice is 900 kg/m$$^{3}$$. A piece of ice is floating in water (of density 1000 kg/m$$^{3}$$). The fraction of volume of the piece of ice outside the water is:

A
0.9
B
0.1
C
0
D
0.7

Solution

## The correct option is A 0.1The forces acting on the ice must balance each other.Hence buoyant force acting upwards = Weight of the ice$$\implies V_{imm}\rho g=Vdg$$$$\implies \dfrac{V_{imm}}{V}=\dfrac{d}{\rho}=0.9$$Hence, the fraction of ice outside water $$=1-0.9=0.1$$Physics

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