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Question

Density of ice is 900 kg/m$$^{3}$$. A piece of ice is floating in water (of density 1000 kg/m$$^{3}$$). The fraction of volume of the piece of ice outside the water is:


A
0.9
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B
0.1
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C
0
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D
0.7
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Solution

The correct option is A 0.1
The forces acting on the ice must balance each other.
Hence buoyant force acting upwards = Weight of the ice

$$\implies V_{imm}\rho g=Vdg$$
$$\implies \dfrac{V_{imm}}{V}=\dfrac{d}{\rho}=0.9$$

Hence, the fraction of ice outside water $$=1-0.9=0.1$$

Physics

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