Derek was giving electricity exam and one of the questions was “Three resistors of resistance 4Ω,
8Ω and 12Ω are connected in parallel. Find the equivalent resistance.” He calculated using the
formula and got the answer as 6Ω. He immediately knew that he did some mistake in the
calculation. How could he possibly know that?

Open in App

Solution

As we know, if we add the resistors in parallel, we get equivalent resistance less than the least resistance in the circuit. As student got the result as 6 ohms, which he finds it wrong, he must have connected the resistors in series later on. As we know, in series the equivalent resistance is more than the greatest one.

Suggest Corrections

Similar questions

Q. Four resistors

5 Ω, 6 Ω, 4 Ω

and

8 Ω

are connected in (a) series and in (b) parallel. Find the equivalent resistance in each case.

Two resistors having resistance $4 Ω$ and $6 Ω$ are connected in parallel. Find their equivalent resistance.

Three resistors of 4 Ω, 12 Ω , and 6 Ω are connected in parallel No. of 12 Ω resistors required to be connected in parallel to reduce the total resistance to half of its original is

How will you connect 6 Ω, 12 Ω, 4 Ω to obtain a net resistance of 8 Ω

Q. Two Resistor

2 Ω

and

4 Ω

are connected in parallel. Two more Resistor

3 Ω

and

6 Ω

are connected in parallel. These two combinations are in series with a battery of emf

5 V

and internal Resistance

0.7 Ω

. Calculate the current through

6 Ω

Resistors.

Join BYJU'S Learning Program