Question

Four resistors $5\Omega ,6\Omega ,4\Omega$ and $8\Omega$ are connected in (a) series and in (b) parallel. Find the equivalent resistance in each case.

Answer 1

In series connection $R_n=R_1+R_2+R_3+R_4=5+6+4+8=23\Omega$

In the parallel connection $\frac{1}{R_n}=\frac{1}{5}+\frac{1}{6}+\frac{1}{4}+\frac{1}{8}=0.74{\Omega }^{-1}$

$R_n=1.34\Omega$