Question

Two resistors of $4\Omega$ and one resistor of $8\Omega$ are connected in the circuit as shown. What will be the equivalent resistance between points A and B in the circuit?

• A. $8\Omega$
• B. $16\Omega$
• C. $1\Omega$
• D. $4\Omega$

Answer 1

The correct option is D $4\Omega$

$4\Omega$ and $4\Omega$ are connected in series.

Whereas their equivalent is parallel with $8\Omega$

$R_s=4\Omega +4\Omega =8\Omega$

$\frac{1}{R_p}=\frac{1}{R_s}+\frac{1}{8}=\frac{1}{8}+\frac{1}{8}=\frac{2}{8}=\frac{1}{4}$

$R_p=4\Omega$.