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B
2xsinx+xcosx
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C
xsinx+x2cosx
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D
2xsinx−x2cosx
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Solution
The correct option is A2xsinx+x2cosx Given, f(x)=x2sinx
So, the derivative of the function is given as df(x)dx=d(x2sinx)dx
Using product rule we have sinxdx2dx+x2dsinxdx=2xsinx+x2cosx