Derive an expression for the electric field E due to a dipole of length ′2a′ at a point distant r from the centre of the dipole on the axial line.
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Solution
Electric field at point P at a distance r from centre of dipole due to +q EB=14πϵ0qBP2 along BP =14πϵ0q(r−a)2 Electric field at point P due to -q is EA=14πϵ0qAP2 along PA =14πϵ0q(r+a)2 Net field at P is given by EP=EB−EA=14πϵ0(q(r−a)2−q(r+a)2)=q4πϵ04ar(r2−a2)2=14πϵ02pr(r2−a2)2
along BP . Where p is the dipole=2qa