Question

# Derive formula for the time period of projectile motion.

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Solution

## Suppose the projectile be thrown with a velocity u at an angle θ from the horizontal. Let 't' be the time taken to reach the top-most point. At this point, the vertical component of velocity will become zero. Using the first equation of motion along vertical direction, vv=uv+avt ⇒0=usinθ−gt ⇒t=usinθg The same time will be taken to reach ground from the highest point. So, time of flight, T=2usinθg

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