By using calculus
1). Acceleration is given as rate of change of velocity
a=dvdt
Now on integrating both sides
a∫t0dt=∫vudv
On solving the above we get
v=u+at
2). Rate of the displacement is equal to velocity
v=dsdt
On integrating the above equation we get
∫s0ds=v∫t0dt
On substituting the value ofv=u+at
We get
s=ut+12at2
3). Distance travelled is equal to average speed time time
s=u+v2t
By using the first equation and substituting the value oft=v−ua
We get
v2=u2+2as