Question

Describe the nuclear fission of ${}_{92}{}^{235}U$.

Answer 1

1. Nuclear fission is a reaction in which the nucleus of an atom splits into two or more smaller nuclei.
2. When the nuclear fission of ${}_{92}{}^{235}U$ takes place, ${}_{56}{}^{139}Ba$ and ${}_{36}{}^{94}Kr$ are released as the fission products of uranium. Uranium-235 splits in around 100 different ways, yielding about 200 different fission products and 2 to 3 neutrons per fission.
3. The nuclear fission of ${}_{92}{}^{235}U$ is given as:

${}_{92}{}^{235}U+{}_0{}^{1}n\to \left[{}_{92}{}^{236}U\right]\to {}_{56}{}^{141}Ba+{}_{36}{}^{92}Kr+3{}_0{}^{1}n+Energy$