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Quantum Numbers

Designation o...

Question

Designation of an orbital with $n = 6$ and $l = 1,$ is:

A

6s

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B

6d

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C

6f

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D

6p

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Solution

The correct option is B 6p
$n = 6$ ; shell $= 6$
$l = 1$ ; subshell $= p$
$m = + l t o - l$
Therefore electron is present in 6p orbital.

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