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Question

Determine all values of a for which the equation cos4x(a+2)cos2x(a+3)=0, possesses solution.Find the solutions.

A
x=nπ±sin1a+3,aϵ[3,2];nϵz
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B
x=2nπ±cos1a+3,aϵ[3,2];nϵz
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C
x=nπ±cos1(a+3),aϵ[3,2];nϵz
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D
x=nπ±cos1a+3,aϵ[3,2];nϵz
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Solution

The correct option is D x=nπ±cos1a+3,aϵ[3,2];nϵz
cos4x(a+2)cos2x(a+3)=0
cos2x=a+2±(a+2)2+4(a+3)2=a+2±(a+4)22
=a+2+a+42,a+2a42=a+3,0
cos2x=a+3x=nπ±cos1a+3
But cos1a+3 is defined when 1a+3+1

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