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Byju's Answer
Standard XII
Physics
1st Equation of Motion
Determine the...
Question
Determine the acceleration due to gravity from the following data of an oblique projectile Y=8t-5tsquare
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Q.
The height y and distance x along the horizontal plane of a projectile on a certain planet are given
y
=
8
t
−
5
t
2
(
m
t
r
)
and
x
=
6
t
(
m
t
r
)
. The acceleration due to gravity is:
Q.
Find the change in range of a projectile if acceleration due to gravity changes by
d
g
Q.
A projectile is projected from ground with initial velocity
→
u
=
u
0
^
i
+
v
0
^
j
.
If acceleration due to gravity (g) is along the negative y-direction then find maximum displacement in x-direction.
Q.
For a projectile projected from ground at an angle
θ
with horizontal,
g
T
2
=
2
R
√
3
, where
T
is time of fight,
R
is horizontal range of projectile,
g
is acceleration due to gravity. The angle of projection
(
θ
)
is
Q.
The instantaneous height
y
of a projectile and the distance covered
x
, are as follows,
x
=
5
t
,
y
=
5
t
−
2
t
2
. What is the acceleration due to gravity if distance is measured in meters and time in seconds.
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