Question

Determine the amount of CaCl2 (i = 2.47) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at 27°C.

Answer 1

We know that,

Here,

R = 0.0821 L atm K^-1mol^-1

M = 1 × 40 + 2 × 35.5

= 111g mol^-1

Therefore, w

= 3.42 g

Hence, the required amount of CaCl₂ is 3.42 g.