Question

Determine the approximate pH of a $0.005$M solution of $H_{2}S{O}_4$?

• A. $1$
• B. $2$
• C. $5$
• D. $9$
• E. $13$

Answer 1

The correct option is B $2$

$\left[H_{2}S{O}_4\right]=0.005M$
$H_{2}S{O}_4\to 2H^{+}+S{O}_4^{2-}$
$\left[H^{+}\right]=2\left[H_{2}S{O}_4\right]=2\times 0.005M=0.01M$
$pH=-log\left[H^{+}\right]=-log\left[H_{2}S{O}_4\right]=-log0.01=2$