Determine the least number which when divided by 3, 4 and 5 leaves a remainder of 2 in each case. [3 MARKS]

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Solution

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Answer: 1 Mark

The LCM of 3, 4 and 5 = 3 $\times$ 4 $\times$ 5 = 60
Therefore, the required number is 2 more than 60.
Hence, the required least number = 60 + 2 = 62.

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