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Question

Determine the magnitude of friction force.
988973_d22dea94469f4997bdb5025f1c8fa1de.png

A
31N
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B
26N
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C
41N
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D
36N
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Solution

The correct option is B 41N
REF.Image.
Limiting friction in x
direction =(μn)(mg)=(0.3)(10)(10)
(Fxl)=30N
Limiting friction in y
direction =(μy)(mg)=40N
(Fye)
Now,
Fye>F1 and Fxl>F2
Thus (friction)y=F1=5N and (friction)x=F2=4N
41N
Ans (C)

1494158_988973_ans_d06506334b294fdeb89c3cd79c2a91a0.png

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