Determine the number of students who appeared in the examination.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is E 70
No. of students who failed only in Maths= 20 (Given)

According to condition given,

Students who failed in Maths and English only + Students who failed in Science and Maths only + Students who failed in all three papers= 30-20= 10.

Therefore, 6+8-x=10 (x being the number of students who failed in all three subjects)

Solving the above equation gives x=4

Student who failed in:-

All three subjects=4

Maths and English only=2

Maths and Science only=4

Science and English only=6

English only=16

Science only=18

Therefore total no. of students= 16+18+20+2+4+6+4=70

Hence answer option E

Suggest Corrections

Similar questions

Q. In an examination, 38% of students failed in Science and 33% failed in Maths while 19% failed in both the subjects. If the number of students who passed in only Science is 700, then determine the total number of students who appeared in the examination.

Q. In a competitive examination,

84 %

of the candidates passed and

780

failed. Find the number of students who appeared for the examination.

Q. In an examination, 30% and 35% student's respectively failed in History and Geography with 27% students failed in both the subjects. If the number of students passing the examination is 248 find the total number of students who appeared the examination.

In an examination, the number of those who passed and the number of those who failed was in the ratio of 3 : 1. Had 48 more appeared, and 8 more failed the ratio of passed to failures would have been 10 : 3. How many students appeared for the examination?

Q. In an examination

235

students passed and

176

students failed. Find the number of students that appeared in the examination.

Join BYJU'S Learning Program