Determine the osmotic pressure of a solution a solution prepared by dissolving 2-5- 10-2g of K2SO4 in 2L of water at 250C- assuming that it is completely dissociated- R-0-0821 L atm K-1mol-1- Molar mass of K2SO4- 174 g mol-1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Osmotic Pressure

Determine the...

Question

Determine the osmotic pressure of a solution a solution prepared by dissolving $2.5 \times 10^{- 2} g$ of $K_{2} S O_{4}$ in 2L of water at $25^{0} C$ , assuming that it is completely dissociated.
( $R = 0.0821 L a t m$ $K^{- 1} m o l^{- 1}$ , Molar mass of $K_{2} S O_{4} = 174 g m o l^{- 1}$ )

Open in App

Solution

Given, mass of $K_{2} S O_{4}$ =25 mg
Volume=2 liter
Temperature=T=298 K
No. of ions produced on dissociation=3
Vant hoff factor=3
$⟹$ Osmotic pressure of the solution $= Π = \frac{i n R T}{V} = (3) \times \frac{1}{2} \times 0.0821 \times 298 = 5.27 \times 10^{- 3}$ atm

Suggest Corrections

Similar questions

Q. Determine the osmotic pressure of a solution prepared by dissolving

2.5 \times 10^{- 2} g

K_{2} S O_{4}

2 L

of water at

25^{\circ} C

assuming that it is completely dissociated.

(T = 0.0821 L a t m K^{- 1} m o l^{- 1}

, Molar mass of

K_{2} S O_{4} = 174 g m o l^{- 1})

Q. Determine the osmotic pressure of a solution prepared by dissolving

2.5 \times 10^{- 2} g

K_{2} S O_{4}

2 L

of water at

25^{\circ} C

, assuming that it is completely dissociated.

(R = 0.0821 L a t m K^{- 1} m o l^{- 1}

, Molar mass of

K_{2} S O_{4} = 174 g m o l^{- 1})

Determine the osmotic pressure of a solution prepared by dissolving 250 g of $K_{2} S O_{4}$ in 2L of water at $25^{o} C$ , assuming that it is completely dissociated.( $R = 0.0821 L a t m K^{- 1} m o l^{- 1}$ , Molar mass of $K_{2} S O_{4}$ = 174 g $m o l^{- 1})$

QUESTION 2.41

Determine the osmotic pressure of a solution prepared by dissolving 25 mg of $K_{2} S O_{4}$ in 2L of water at $25^{\circ} C$ , assuming that it is completely dissociated.

Q. Calculate the osmotic pressure of a solution prepared by dissolving

0.025 g

K_{2} S O_{4}

2.0

litres of water at

25^{o} C

assuming that

K_{2} S O_{4}

is: (completely dissociated)
(mol. wt. of

K_{2} S O_{4}

174 g m o l^{- 1}

)

Join BYJU'S Learning Program

Determine the osmotic pressure of a solution a solution prepared by dissolving 2.5×10−2g of K2SO4 in 2L of water at 250C, assuming that it is completely dissociated.(R=0.0821 L atm K−1mol−1, Molar mass of K2SO4=174gmol−1)

Given, mass of K2SO4=25 mgVolume=2 literTemperature=T=298 KNo. of ions produced on dissociation=3Vant hoff factor=3⟹ Osmotic pressure of the solution=Π=inRTV=(3)×12×0.0821×298=5.27×10−3 atm

Determine the osmotic pressure of a solution a solution prepared by dissolving $2.5 \times 10^{- 2} g$ of $K_{2} S O_{4}$ in 2L of water at $25^{0} C$ , assuming that it is completely dissociated.
( $R = 0.0821 L a t m$ $K^{- 1} m o l^{- 1}$ , Molar mass of $K_{2} S O_{4} = 174 g m o l^{- 1}$ )

Given, mass of $K_{2} S O_{4}$ =25 mg
Volume=2 liter
Temperature=T=298 K
No. of ions produced on dissociation=3
Vant hoff factor=3
$⟹$ Osmotic pressure of the solution $= Π = \frac{i n R T}{V} = (3) \times \frac{1}{2} \times 0.0821 \times 298 = 5.27 \times 10^{- 3}$ atm