Determine the osmotic pressure of a solution prepared by dissolving 2-5- 10-2g of K2SO4 in 2L of water at 25-C assuming that it is completely dissociated- T - 0-0821 L atm K-1 mol-1- Molar mass of K2SO4 - 174 g mol-1

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Standard XII

Chemistry

Osmotic Pressure

Determine the...

Question

Determine the osmotic pressure of a solution prepared by dissolving $2.5 \times 10^{- 2} g$ of $K_{2} S O_{4}$ in $2 L$ of water at $25^{\circ} C$ assuming that it is completely dissociated.
$(T = 0.0821 L a t m K^{- 1} m o l^{- 1}$ , Molar mass of $K_{2} S O_{4} = 174 g m o l^{- 1})$

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Solution

Given, that mass of $K_{2} S O_{4}$ , w=25 mg=0.025 g
Volume V=2 L
T=25+273 =298 K
The reaction of dissociation of $K_{2} S O_{4}$ is,
$K_{2} S O_{4} \to 2 K^{+} + S O_{4}^{2 -}$

Number of ions produced=3=van't Hoff factor

Hence, $π = i C R T$
$⟹ π = 3 \times \frac{0.025}{174} \times 0.5 \times 0.0821 \times 298 = 5.27 \times 10^{- 3} a t m$

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QUESTION 2.41

Determine the osmotic pressure of a solution prepared by dissolving 25 mg of $K_{2} S O_{4}$ in 2L of water at $25^{\circ} C$ , assuming that it is completely dissociated.

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Determine the osmotic pressure of a solution prepared by dissolving 2.5×10−2g of K2SO4 in 2L of water at 25∘C assuming that it is completely dissociated.(T=0.0821 L atm K−1 mol−1, Molar mass of K2SO4=174 g mol−1)

Given, that mass of K2SO4, w=25 mg=0.025 gVolume V=2 LT=25+273 =298 KThe reaction of dissociation of K2SO4 is,K2SO4→2K++SO2−4Number of ions produced=3=van't Hoff factorHence, π=iCRT⟹π=3×0.025174×0.5×0.0821×298=5.27×10−3 atm

Determine the osmotic pressure of a solution prepared by dissolving $2.5 \times 10^{- 2} g$ of $K_{2} S O_{4}$ in $2 L$ of water at $25^{\circ} C$ assuming that it is completely dissociated.
$(T = 0.0821 L a t m K^{- 1} m o l^{- 1}$ , Molar mass of $K_{2} S O_{4} = 174 g m o l^{- 1})$