Determine the oxidation number of $C l$ in $N a O C l$ ?

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Solution

It is similar to hypochlorous acid ( $H O C l$ ). Oxidation state of $O$ is -2, $N a$ has +1. therefore
$1 + (- 2) + x = 0$
$x = + 1$
Oxidation number of $C l$ in $N a O C l$ is $+ 1$ .

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