Question

Determine the oxidation number of sulphur in $H_{2}S{O}_4$.

• A. $+6$
• B. $+4$
• C. $+2$
• D. $0$

Answer 1

Answer: (A)

$+6$

We know that the oxidation number of $H=+1$ and $O=-2$
Consider the oxidation state of $S$ to be $x$,

$2\left(1\right)+x+4(-2)=0$
$\Rightarrow x=+6$

Thus, the oxidation state of $S$ to be $+6$ in $H_{2}S{O}_4$.