Determine the shape of the following molecules using the VSEPR model.

$B e C l_{2}, B C l_{3}, S i C l_{4}, A s F_{5}, H_{2} S a n d P H_{3}$

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Solution

The shape according to VSEPR theory is given below :
Molecule Number of electron pairs around central atom
Molecular geometry
Bond angles
$B e C l_{2}$ 2 Linear $180^{o}$
$B C l_{3}$ 3 trigonal planar
$120^{o}$
$S i C l_{4}$ 4 tetrahedral ${109.5}^{o}$
$A s F_{5}$ 5 trigonal bipyramidal
three $120^{o}$ , two $90^{o}$
$H_{2} S$ 6 non linear/bent $92^{o}$
$P H_{3}$ 5 trigonal pyramidal
${93.5}^{o}$

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Molecule	Number of electron pairs around central atom	Molecular geometry	Bond angles
$B e C l_{2}$	2	Linear	$180^{o}$
$B C l_{3}$	3	trigonal planar	$120^{o}$
$S i C l_{4}$	4	tetrahedral	${109.5}^{o}$
$A s F_{5}$	5	trigonal bipyramidal	three $120^{o}$ , two $90^{o}$
$H_{2} S$	6	non linear/bent	$92^{o}$
$P H_{3}$	5	trigonal pyramidal	${93.5}^{o}$