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EMF

Determine the...

Question

Determine the standard emf of the cell and standard free energy change of the cell reaction.
$Z n {/ Z n}^{2 +} ∥ {N i}^{2 +} / N$
$E^{o}$ ${Z n}^{2 +} / Z n = - 0.76 V$
$E^{o}$ ${N i}^{2 +} / N i = - 0.25 V$

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Solution

$Z n {, Z n}^{2 +} ∥ {N i}^{2 +}, N i$
$E_{c e l l}^{\circ} = E_{R}^{\circ} - E_{L}^{\circ} = - 0.25 - (- 0.76) = + 0.51 V$
$E_{c e l l}$ is a positive $∴ Δ G^{\circ} = -$ ve
$∴ Δ G^{\circ} = - n F E_{c e l l}^{\circ}$
$n = 2$ electrons
$∴ Δ G^{\circ} = - 2 \times 96495 \times 0.51 = - 97460 j o u l e s = - 97.46 k J$

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Z n | Z n^{2 +} | | N i^{2 +} | N i

Z n^{2 +} | Z n

N i^{2 +} | N i

- 0.76 V

- 0.25 V

E^{o}

Z n \to Z n^{2 +} + 2 e^{-}; E^{o} = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E^{o} = + 0.41 V

F e^{2 +} + Z n \to Z n^{2 +} + F e

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Z n ⟶ {Z n}^{2 +} + 2 e^{-}

E^{o} = + 0.76 V

F e ⟶ {F e}^{2 +} + 2 e^{-}

E^{o} = + 0.41 V

{F e}^{2 +} + Z n ⟶ {Z n}^{2 +} + F e

E^{o}

Z n \to {Z n}^{2 +} + 2 e^{-}; E^{o} = + 0.76 V

F e \to {F e}^{2 +} + 2 e^{-}; E^{o} = + 0.41 V

{F e}^{2 +} + Z n \to {Z n}^{2 +} + F e

Z n^{2 +} + 2 e^{-} \to Z n (s); E^{o} = - 0.76 V

C a^{2 +} + 2 e^{-} \to C a (s); E^{o} = - 2.87 V

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