Question

Determine the value of $a$ for which the equation:

$\frac{8d+10-d}{3}=\frac{d(3+4)+a}{3}$ has infinitely many solutions for all $d$.

• A. -10
• B. 10
• C. 15
• D. 20

Answer 1

The correct option is B 10

Given, $\frac{8d+10-d}{3}=\frac{d(3+4)+a}{3}$

$\Rightarrow 8d+10-d=3d+4d+a$

$\Rightarrow 7d+10=7d+a$

$\Rightarrow a=10$