${\frac{1}{5}}^{t h}$ part of a house been painted. What percent of the house is still to be painted.

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Solution

Part of house to be painted $= 1 - \frac{1}{5} = \frac{4}{5}$
Therefore,
Percentage of house still to be painted $= \frac{\frac{4}{5}}{1} \times 100 = 80 %$

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15th part of a house been painted. What percent of the house is still to be painted.

Part of house to be painted =1−15=45Therefore,Percentage of house still to be painted =451×100=80%

${\frac{1}{5}}^{t h}$ part of a house been painted. What percent of the house is still to be painted.

Part of house to be painted $= 1 - \frac{1}{5} = \frac{4}{5}$
Therefore,
Percentage of house still to be painted $= \frac{\frac{4}{5}}{1} \times 100 = 80 %$