1√(49) √(48) =1( 7 4√(3)) [∵ 48 = 16× 3] =1( 7 4√(3))×( 7+4√(3))( 7+4√(3)) =( 7+4√(3))( 49 48 ) =7+4√(3) Hence, the correct answer is option (d). ...

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Byju's Answer

Standard IX

Mathematics

Rationalisation

1√49-√48 is e...

Question

$\frac{1}{\sqrt{49} - \sqrt{48}}$ is equal to

\frac{1}{2} (7 - 4 \sqrt{3})

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7 - 4 \sqrt{3}

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7 + 6 \sqrt{3}

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7 + 4 \sqrt{3}

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Solution

The correct option is D $7 + 4 \sqrt{3}$
$\frac{1}{\sqrt{49} - \sqrt{48}}$
$= \frac{1}{(7 - 4 \sqrt{3})}$ $[∵ 48 = 16 \times 3]$
$= \frac{1}{(7 - 4 \sqrt{3})} \times \frac{(7 + 4 \sqrt{3})}{(7 + 4 \sqrt{3})}$
$= \frac{(7 + 4 \sqrt{3})}{(49 - 48)}$
$= 7 + 4 \sqrt{3}$
Hence, the correct answer is option (d).

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1√49−√48 is equal to

The correct option is D 7+4√31√49−√48 =1(7−4√3) [∵48=16×3] =1(7−4√3)×(7+4√3)(7+4√3) =(7+4√3)(49−48) =7+4√3 Hence, the correct answer is option (d).

$\frac{1}{\sqrt{49} - \sqrt{48}}$ is equal to