Question

Solve:
$\frac{\sqrt{98}\times \sqrt{12}\times \sqrt{48}}{\sqrt{49}\times \sqrt{24}\times \sqrt{8}}$

Answer 1

Given that:

$\frac{\sqrt{98}\times \sqrt{12}\times \sqrt{48}}{\sqrt{49}\times \sqrt{24}\times \sqrt{8}}$

So

$=\frac{\sqrt{49\times 2}\times \sqrt{12}\times \sqrt{24\times 2}}{\sqrt{49}\times \sqrt{24}\times \sqrt{8}}$

$=\frac{\sqrt{49}\times \sqrt{2}\times \sqrt{12}\times \sqrt{24}\times \sqrt{2}}{\sqrt{49}\times \sqrt{24}\times \sqrt{8}}$

$=\frac{\sqrt{2}\times \sqrt{12}\times \sqrt{2}}{\sqrt{8}}$

$=\frac{2\sqrt{4\times 3}}{\sqrt{8}}$

$=\frac{4\sqrt{3}}{2\sqrt{2}}$

$=\sqrt{2}\sqrt{3}$

$=\sqrt{6}$