Prove that:(i) 13+√7+1√7+√5+1√5+√3+1√3+1=1(ii) 11+√2+1√2+√3+1√3+√4+1√4+√5+1√5+√6+1√6+√7+1√7+√8+1√8+√9=2
Fill in the blanks to make the following statements true:
(i) (− 5) + (− 8) = (− 8) + (…)
(ii) − 53 + … = − 53
(iii) 17 + … = 0
(iv) [13 + (− 12)] + (…) = 13 + [(− 12) + (− 7)]
(v) (− 4) + [15 + (− 3)] = [(− 4) + 15] +
Re-arrange suitably and find the sum in each of the following :
(i)1112+−173+112+−252
(ii)−67+−56+−49+−157
(iii)35+73+95+−1315+−73
(iv) 413+−58+−813+913
(v)23+−45+13+25
(vi) 18+512+27+712+97+−516