7x-4 x-2 - 4 3 5y-2 2y-7 -2 3y-1 - 7 2 find the value of x and y-

7x + 4x + 2 = 43 21x+12=4x+8 x= 417 5y 2(2y 7) = 2(3y 1) + 72 5y 4y+14=6y 2+72 5y=14 32 y=52 ...

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Solving Equations with Variables on Both Sides

7x+4 x+2 = 4 ...

Question

$\frac{7 x + 4}{x + 2} = \frac{4}{3}$
$5 y - 2 (2 y - 7) = 2 (3 y - 1) + \frac{7}{2}$ find the value of $x$ and $y$ .

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Solution

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5 y - 2 (2 y - 7) = 2 (3 y - 1) + \frac{7}{2}

\frac{2 x - 3 y}{5 x - 4 y} = \frac{3}{2}

\frac{7 x + 4 y}{7 x - 4 y}

3 (y - 7) - 2 (3 y - 4) = (2 - 5 y)

x = \frac{1}{7 + 4 \sqrt{3}}

y = \frac{1}{7 - 4 \sqrt{3}}

5 x^{2} - 7 x y - 5 y^{2}

x = 7 + 4 \sqrt{3}, y = 7 - 4 \sqrt{3}

\frac{1}{x^{2}} + \frac{1}{y^{2}}

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