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Question

If 2xāˆ’3y5xāˆ’4y=32, then the value of 7x+4y7xāˆ’4y is

A
4219
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B
4317
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C
43
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D
43
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Solution

The correct option is C 43
2x3y5x4y=32
2(2x3y)=3(5x4y)
xy=611
7x4y=4244=2122
Applying componendo and dividendo, we get
7x+4y7x4y=431=43

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